select NAME, rank, count, surname_entries.id 'wiki_id' from surnames left join surname_entries on surname_entries.surname = surnames.name and surname_entries.entry_type = 1 where index2 = 'NN' order by rank asc limit 0,100 Surnames > N > NN > %22

Surnames > N > NN > %22

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
NA NC ND NE NG NH NI NJ NK NN NO NS NT NU NW NY NZ
NNA

Full Surname List Starting with %22(Alphabetical)